(n^2-n-6)/(n^2)-(2n+12)/n=(n-6)/2n

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Solution for (n^2-n-6)/(n^2)-(2n+12)/n=(n-6)/2n equation: 



(n^2-n-6)/(n^2)-(2n+12)/n=(n-6)/2n

We move all terms to the left:

(n^2-n-6)/(n^2)-(2n+12)/n-((n-6)/2n)=0



Domain of the equation: n^2!=0

n^2!=0/

n^2!=√0

n!=0

n∈R





Domain of the equation: n!=0

n∈R





Domain of the equation: 2n)!=0

n!=0/1

n!=0

n∈R



We calculate fractions

We do not support enpression: n^4

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